5=-6t^2+24t+6

Solution for 5=-6t^2+24t+6 equation:

5=-6t^2+24t+6

We move all terms to the left:

5-(-6t^2+24t+6)=0

We get rid of parentheses

6t^2-24t-6+5=0

We add all the numbers together, and all the variables

6t^2-24t-1=0

a = 6; b = -24; c = -1;
Δ = b2-4ac
Δ = -242-4·6·(-1)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-10\sqrt{6}}{2*6}=\frac{24-10\sqrt{6}}{12}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+10\sqrt{6}}{2*6}=\frac{24+10\sqrt{6}}{12}
$